10x^2-16x-18=0

Solution for 10x^2-16x-18=0 equation:

10x^2-16x-18=0

a = 10; b = -16; c = -18;
Δ = b2-4ac
Δ = -162-4·10·(-18)
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{61}}{2*10}=\frac{16-4\sqrt{61}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{61}}{2*10}=\frac{16+4\sqrt{61}}{20}
$